Data : sample

BOD

Data Sheet:

Time
Day
Obs.#
Initial reading(ml)
Final reading(ml) Solution added (ml) Mean Solution added (ml)
DO
(mg/L)
BOD
(mg/L)
0 1 24.0 28.2 4.2 4.1 8.2 0
2 28.2 32.2 4.0
2 1 6.0 9.5 3.5 3.5 7.0 1.2
2 9.5 13 3.5
7 1 25.3 27.5 2.2 2.15 4.3 3.9
2 27.5 29.6 2.1

Facal Coliform

Result & Calculation:

Membrane Filter Method:

Facal Coliform = TNTC
(TNTC = Too Numerous TO Count)

Multiple Tube Method:

Facal Coliform = A small amount of gas presence
in the inverted tube

Number of tubes giving positive reaction out of 5 of 10ml each MPN
0 0
1 2.2
2 5.1
3 9.2
4 16.0
5 intermediate

Result:

Facal Coliform (FC) = positive

Total Coliform

Result & Calculation:

Membrane Filter Method:

Total Coliform = TNTC
(TNTC = Too Numerous TO Count)

Multiple Tube Method:
Total Coliform = A small amount of gas presence in the inverted tube

Number of tubes giving positive reaction out of 5 of 10ml each MPN
0 0
1 2.2
2 5.1
3 9.2
4 16.0
5 intermediate

Result:
Total Coliform (TC) = positive

Arsenic

Result & Calculation:

Field Kit Method:
Arsenic Concentration = 55×5
= 275 micro gram/litre
= 0.0003 g/L
= 0.3 mg/L

SDDC Method:
Arsenic Concentration
= 0.223×80×20
= 356.8 microgram/litre
= 0.00036 g/L
= 0.36 mg/L

Result:
Field Kit Method:
Arsenic Concentration = 0.3 mg/L
SDDC Method:
Arsenic Concentration = 0.36 mg/L

alum

Data Sheet , Calculation Result:

DATA:

Obs.#
Dose (mg/L)
Amount Sample (ml) Alum solution Added (ml) Turbidity
NTU
Value of pH
1 20 498 2 4.2 6.3
2 40 496 4 2.2 6.9
3 60 494 6 0.78 6.8
4 80 492 8 0.58 7.0
5 100 490 10 0.42 7.0
6 120 488 12 0.51 7.0
7 140 486 14 0.35 6.9
8 180 482 18 0.30 6.8
9 220 478 22 0.38 6.7
10 280 472 28 0.38 6.8
11 340 466 34 0.55 6.6
12 400 460 40 0.60 6.7

From the plot of the turbidity versus the coagulant (alum) dose,(in a plain graph paper) the optimum dose of alum =

Result :
The optimum dose of alum =

Chemical oxygen demand (COD)

DATA & CALCULATION SHEET:

COD(mg/l) = [ml. of KMnO4 used X 100/ ml. of sample used ] X MF
= 5.5 X 100/ 100
= 5.5 (mg/l)

RESULT :

Chemical oxygen demand (COD) of the water sample is 5.5mg/ l

BOD

DATA SHEET & CALCULATION:

Data :

Time
Day
Obs.#
Initial reading(ml)
Final reading(ml) Solution added (ml) Mean Solution added (ml)
DO
(mg/L)
BOD
(mg/L)
0 1 24.0 28.2 4.2 4.1 8.2 0
2 28.2 32.2 4.0
2 1 6.0 9.5 3.5 3.5 7.0 1.2
2 9.5 13 3.5
7 1 25.3 27.5 2.2 2.15 4.3 3.9
2 27.5 29.6 2.1

DO (mg/l) = [ml. of 0.025 (N) Sodium Thiosulfate added ] X 2
DO (mg/l)0 = 4.1 X2 = 8.2
The BOD of the sample at t day is given by
BODt = [DOI - DOf ] X D.F.

Where
D.F. = 1 , DOI = initial DO , DOf = final DO

The two day BOD of the sample
BOD2 (mg/l) = [DO0- DO2] X D.F.
= (8.2-7.0) X1
= 1.2 mg/L

The seven day BOD of the sample

BOD7 (mg/l) = [DO0- DO7] X D.F.
= (8.2 – 4.3) X1
= 3.9 mg/L

BODt (mg/l) = L0(1-e-kt)

1.2 = L0 (1-e-2k) -----------(1)
and 3.9 = L0( 1-e-7k ) -----------(2)

by trial and error
k= 0.03
L0=20.61

The five day BOD of the sample

BOD5 (mg/l) = L0 (1-e-kt)
= 20.61(1- e-0.03*5)
= 2.87 (mg/l)

RESULT :

The five day BOD of the sample BOD5 (mg/l) = 2.87 mg/L

solids

Result & Calculation:

Type Wt. Of Beaker (gm) Wt. Of Beaker +Residual (gm) Wt. Of Residual (gm)
Total solids (TS) 50.0752 50.0902 0.015
Dissolved solids (DS) 50.1134 50.1278 0.0144
Suspended solids (SS) = (TS- SS) = 0.0006

Volume of Sample = 100 ml

Total solids (TS) mg/L =
{Wt. Of TS (mg) in Beaker × 1000/ volume of sample}
= (0.015× 1000) × 1000/100
= 150
Dissolved solids (SS) mg/L =
{Wt. Of SS (mg) in Beaker × 1000/ volume of sample}
= (0.0144× 1000) × 1000/100
= 144
Suspended solids (SS) mg/L = (TS –DS)
= (150 - 144)
= 6

Total solids (TS) = 150 mg/L
Dissolved solids (SS) = 144 mg/L
Suspended solids (SS) mg/L = 6 mg/L